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3. ro?ník / Re: Principy programovacich jazykov
« on: 05.03.2010, 14:24:27 »
cvicenie 3: MOCNINA,funguje aj dalsia operacia zamocninou v jednom vyraze (napr 2^3+3)
Code: [Select]
/**********************************************************/
/* Interpretacia vyrazov */
/*--------------------------------------------------------*/
/* E -> T { ( "+" | "-" ) T } */
/* T -> F { ( "*" | "/" ) F } */
/* F -> cislo | "(" E ")" */
/**********************************************************/
#include <stdio.h>
#include <stdafx.h>
#include <math.h>
/*--------------------------------------------------------*/
/* syntakticke procedury */
/*--------------------------------------------------------*/
int sym; /* vstupny symbol */
int E(void),T(void),F(void),G(void); /* prototypy */
int E(void){
int op;
int h1,h2;
h1=T();
while(sym=='+' || sym=='-'){
op=sym;
sym=getchar();
h2=T();
if(op=='+')h1=h1+h2;
else h1=h1-h2;
}
return (h1);
}
int T(void){
int op;
int h1,h2;
h1=F();
while(sym=='*' || sym=='/'){
op=sym;
sym=getchar();
h2=F();
if(op=='*')h1=h1*h2;
else h1=h1/h2;
}
return (h1);
}
int G(void){
int h1;
switch(sym){
case '0':case '1':case '2':case '3':case '4':
case '5':case '6':case '7':case '8':case '9':
h1=sym-'0';
while((sym=getchar())>='0' && sym<='9')
h1=h1*10+sym-'0';
break;
case '(':
sym=getchar();
h1=E();
if(sym==')')sym=getchar();
else printf("\nChybajuca prava zatvorka\n");
break;
default: printf("\nNedovoleny symbol %c\n",sym);
h1=0;
break;
}
return (h1);
}
int F(void){
int op;
double h1,h2;
h1=G();
if(sym=='^'){
sym=getchar();
h2=G();
return (int)pow(h1,h2);
}
return (h1);
}
/*--------------------------------------------------------*/
/* hlavny program */
/*--------------------------------------------------------*/
int main(void){
sym=getchar();
printf("\nVysledok: %d\n",E());
sym=getchar();
return(0);
}
(14/16bodov),kedze nemam cas tak max pre dvoch ludi ,kto ma zaujem postnite sem info 
