Author Topic: LS  (Read 125780 times)

MKI

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Re: LS
« Reply #25 on: 08.11.2007, 02:50:58 »
to si nikto nechce zarobit ? ci to uz sme vam za tie prve dve rocniky tolko penazi dali ze uz nepotrebujete ? :DD
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Ing. nemtom

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Re: LS
« Reply #26 on: 08.11.2007, 04:18:11 »
to si nikto nechce zarobit ? ci to uz sme vam za tie prve dve rocniky tolko penazi dali ze uz nepotrebujete ? :DD

tak nejak :D:D, mojou srdcovkou je druhy rocnik s OOP :D:D
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Re: LS
« Reply #27 on: 09.11.2007, 05:46:45 »
ma niekto zadanie synteza prevodnika z BCD do Johnsonovho kodu?

m!x41

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Re: LS
« Reply #28 on: 09.11.2007, 17:03:49 »
SERIOZNE, kto tu vie robit multiplex, demultiplex, pamate a nejake puzdra ci co?
mam zadanie f=[2,8,9,12,13(0,5,10,15)]

rolin21

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Re: LS
« Reply #29 on: 10.11.2007, 15:39:52 »
zdravim .. vie mi niekto poradit, ako by mla vyzerat schema ak mam pouzit 3 vstupove NAND, 3 vstupove NOR, AND-OR-INVERT? musi schema obsahovat vylucne len 3 vstupove NAND, alebo mozem tam pouzit okrem toho aj napd. 2 vstupove NAND ?

zadanie mam f=(a,b,c,d)=[3,5,7,10,13,14(1,4,6)]

MKI

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Re: LS
« Reply #30 on: 10.11.2007, 16:24:58 »
sakraa ludia v pondelok treba odovzdat :(( ja mam bcd do gray ...
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BCAA

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Re: LS
« Reply #31 on: 10.11.2007, 19:11:26 »
zdravim .. vie mi niekto poradit, ako by mla vyzerat schema ak mam pouzit 3 vstupove NAND, 3 vstupove NOR, AND-OR-INVERT? musi schema obsahovat vylucne len 3 vstupove NAND, alebo mozem tam pouzit okrem toho aj napd. 2 vstupove NAND ?

zadanie mam f=(a,b,c,d)=[3,5,7,10,13,14(1,4,6)]



tak ked mozes pouzit len 3 vstupove  a chces 2 vtupovy    tak na ten 3 vstupovy NAND privedies tie 2 vstupy co chces a treti tam privedies logicku 1

MKI

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Re: LS
« Reply #32 on: 10.11.2007, 19:15:57 »
zdravim .. vie mi niekto poradit, ako by mla vyzerat schema ak mam pouzit 3 vstupove NAND, 3 vstupove NOR, AND-OR-INVERT? musi schema obsahovat vylucne len 3 vstupove NAND, alebo mozem tam pouzit okrem toho aj napd. 2 vstupove NAND ?

zadanie mam f=(a,b,c,d)=[3,5,7,10,13,14(1,4,6)]



tak ked mozes pouzit len 3 vstupove  a chces 2 vtupovy    tak na ten 3 vstupovy NAND privedies tie 2 vstupy co chces a treti tam privedies logicku 1

nechces si zarobit ked to vies robit ? :D
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trek

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Re: LS
« Reply #33 on: 10.11.2007, 19:23:18 »
sakra do pondelka to nestihnem :j_cry: ...no keby sa nasla nejaka dobra dusa co to vie robit stedro sa odmenim :j_wink: synteza BCD do johnsnovho

m!x41

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Re: LS
« Reply #34 on: 11.11.2007, 05:25:24 »
fakt nikto kto by pomohol s multiplexormi, demultiplexormi, pamatami a puzdrami??? zvysok mam, len toto je pre mna ruskom tajomstva zahalene, kedze na cvikach sa to jaksi neprecvicilo, v prednaskach som nic nenasiel a ujo google tiez nevie velmi pomoct ako nato...

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Re: LS
« Reply #35 on: 11.11.2007, 23:15:58 »
idu vam tie aplety na syntlogu? Quine-McCluskey hlavne...
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Re: LS
« Reply #36 on: 12.11.2007, 00:23:19 »
idu vam tie aplety na syntlogu? Quine-McCluskey hlavne...

som skusal na syntlogu az 3 aplety ale nesiel ani jeden ked som dal ze Aplikacia, aj ten quine som skusal a nejde, potom ten na implikanty a nepustilo dalej poz adani udajov

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omg nie je podla coho robit zadanie :( multiplexory, logicke puzdra, logicke cleny atd vobec nechapem, akurat formy minimalizacie mam a sheffer+peirce :(
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MKI

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Re: LS
« Reply #37 on: 12.11.2007, 03:30:20 »
tak aspon doporucte niekoho kto to vie nech ho mozme spamovat :D
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trek

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Re: LS
« Reply #38 on: 12.11.2007, 05:09:56 »
oh shit...poradte aspon ako sa mam vyhovoritm ze preco to nemam spravene:D

wlade

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Re: LS
« Reply #39 on: 12.11.2007, 05:47:17 »
oh shit...poradte aspon ako sa mam vyhovoritm ze preco to nemam spravene:D

jednoducha vec, ze nesla stranka syntlogu :D
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manro

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Re: LS
« Reply #40 on: 12.11.2007, 15:09:56 »
kua neviete mi poradit nejaky dobry soft abo aplet na IDNF z mriezky prostych implikantov (Q-McC)?
Mam rovnake zadanie ako rolin21... f=(a,b,c,d)=[3,5,7,10,13,14(1,4,6)]
The Pumping Lema

Let L be any regular language that has infinitely many words. Then there exist three strings x, y, and z such that y is non-null and all strings of the form
  xynz  for n=1,2,3,...

are words in L.

kane77

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Re: LS
« Reply #41 on: 12.11.2007, 17:49:22 »
http://rabbit.eng.miami.edu/info/datasheets/

tu su nejake suciastky, mozu sa hodit...
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petrushka

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Re: LS
« Reply #42 on: 12.11.2007, 19:57:51 »
neviete ako to vlastne mame odovzdavat, teda v akej forme (tlacenej, elektronickej) + ti co su v AJ triede - treba aj po anglicky?  bn
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Ing.Veduci

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Re: LS
« Reply #43 on: 12.11.2007, 21:09:55 »
my sme s subom odovzdavali tlacene
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m!x41

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Re: LS
« Reply #44 on: 12.11.2007, 21:13:55 »
a je to tu... kto uz ma druhe zadanie?
nema niekto elektricky zamok (X2,X1,X1,X3; RS; NOR) ???

pUf

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Re: LS
« Reply #45 on: 15.11.2007, 00:46:20 »
my sme este prve neodovzdali.. a ani som to este nevidel :j_rolleyes:
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rizek

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Re: LS
« Reply #46 on: 16.11.2007, 16:53:58 »
Sevas ludze, som nasiel take pdf-ko z ceskej vysokej skoly technickej (jasneze ze ne z TUKE, to by tam nejake materialy aj museli byt :P ) , mno a v nom sa vysvetluju tie logicke systemy od uplneho zaciatku, od piky (boolova algebra) cez funkcie a prevodniky az po pouzitie vhodnych suciastok a dalej- neni to ziadne vypracovane zadanie ale kto chce pochopit LS taa, vrelo odporucam :-) , tu to je: radio.feld.cvut.cz/courses/CS/web/CS/CS-Spinaci%20a%20cislicova%20technika94.pdf
PS: to pdf neni volne kopirovatelne a siritelne bez suhlasu autorov taze kto ma moralne zabrany nech necita :D
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MKI

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Re: LS
« Reply #47 on: 16.11.2007, 22:07:21 »
fakt nikto za peniaze nespravi z BCD do Grayovho kodu ?
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kane77

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Re: LS
« Reply #48 on: 16.11.2007, 22:35:06 »
fakt nikto za peniaze nespravi z BCD do Grayovho kodu ?

ved na ftp mas zadania.. a tusim aj toto som tam videl...
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MKI

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Re: LS
« Reply #49 on: 16.11.2007, 22:42:38 »
toto tam teda neje -  neviem zmenit z ineho ....
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